x^2+2x-108=-10x+3

Solution for x^2+2x-108=-10x+3 equation:

x^2+2x-108=-10x+3

We move all terms to the left:

x^2+2x-108-(-10x+3)=0

We get rid of parentheses

x^2+2x+10x-3-108=0

We add all the numbers together, and all the variables

x^2+12x-111=0

a = 1; b = 12; c = -111;
Δ = b2-4ac
Δ = 122-4·1·(-111)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-14\sqrt{3}}{2*1}=\frac{-12-14\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+14\sqrt{3}}{2*1}=\frac{-12+14\sqrt{3}}{2}
$